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Grade of concrete – M20
Mix Ratio(M20) = 1 : 1.5 : 3
1 – Cement
1.5 – Sand
3 – Blue metal
Volume required for 1 m3 concrete
We find out the volume of concrete in wet condition 1m3 (After the consolidation of Cement + sand + water). So in dry conditions, we have to add 30 to 35% sand bulkage and add 20% for wastage.
Accounting bulkage of sand - 34%
Accounting wastage of material -20%
Dry volume of concrete = 1.54
Ratio = 1+1.5+3 = 5.5
Calculation of Volume of Cement in 1m3 of Concrete
Volume of Cement required (1m3)= (1/5.5) x 1.54 = 0.2798 m3
Here,
Cement = 1 (1:1.5:3)
Concrete = 1+1.5+3 = 5.5
Cement required (1m3) in kg
= volume of Cement X Density of Cement
Density of Cement = 1440 kg/ m3
= 0.2798 X 1440 = 403.19 kg
Cement required (1m3) in Bags
= 403.29/50 = 8.06 bags
Calculation of Volume of Sand in 1m3 of Concrete
Sand = 1.5 (1:1.5:3)
Concrete = 1+1.5+3 = 5.5
Sand Required in m3
= (1.5/5.5) x 1.54 = 0.42 m3
Sand required in cubic ft
1m3 = 35.31 cft
Therefore,
= 0.42 x 35.31= 14.83 Cft
(Or)
Sand required in weight kg
Density of sand = 1500–1550 kg/cum
= 0.42 X 1500 = 630 kg
Calculation of Volume of aggregate in 1m3 of Concrete
Aggregate = 3 (1:1.5:3)
Concrete parts = 1+1.5+3 = 5.5
Aggregate required in m3
= (3/5.5) x 1.54 = 0.84 m3
Aggregate required in cubic ft
= 0.84 x 35.31 = 29.66 Cft
(Or)
Aggregate required in weight kg
Density of aggregate = 1520 - 1680 kg/cum
= 0.84 x 1520 = 1276.8 kg
Total amount of materials required for 1m3 of Concrete
1m3 of Concrete
Cement - 8 bags/ 1m3
Sand - 14.83 Cft/ 1m3
Aggregate - 29.66 Cft/ 1m3
If you need quantity for (Different volume) 10 m3 volume
Cement = 8 x 10 = 80 Bags/10 m3
Sand = 14.83 x 10 = 148.3 cft/10 m3
Aggregate = 29.66 x 10 = 296.6 cft/10m3
Calculation of Volume of water in 1m3 of Concrete
Water cement ratio 0.5 for a bag = 0.5 x 50 ( weight of a bag) = 25 litre
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Calculations